Maths performs full-wave rectification by multing a signal to CH.2 (normal) and CH.3 (inverted) into OR OUT

Full-wave rectification requires both the original signal and its inverted copy presented to the OR bus. On Maths: mult the signal to CH.2 Signal IN (Attenuvertor full CW) and to CH.3 Signal IN (Attenuvertor full CCW = inverted). Take OR OUT. The OR selects the larger: during positive swings CH.2 wins; during negative swings the inverted CH.3 wins, appearing positive. Both half-cycles emerge positive, doubling the modulation rate with all-positive values.

Examples

CV → CH.2 Signal IN (Att full CW) and CH.3 Signal IN (Att full CCW). OR OUT → VCO FM. A sine LFO patched this way doubles the modulation rate.

Assessment

Without a mult, how would you route a single signal to both CH.2 and CH.3 for full-wave rectification, and what happens if attenuvertors are not symmetrically set?